Three resistors of resistances 11 Ω, 22 Ω and 33 Ω are connected in parallel. Their equivalent resistance is equal to

To find the equivalent resistance (R) of resistors connected in parallel, the standard formula is the reciprocal of the sum of the reciprocals of individual resistances: 1/R = 1/R1 + 1/R2 + 1/R3. Given the resistances are 11 ̐, 22 ̐, and 33 ̐, the calculation is 1/R = 1/11 + 1/22 + 1/33. To solve this, find a common denominator, which is 66. Thus, 1/R = 6/66 + 3/66 + 2/66 = 11/66. Simplifying this gives 1/R = 1/6. Taking the reciprocal to find R, we get R = 6 ̐. This confirms that in a parallel circuit, the equivalent resistance is always smaller than the smallest individual resistor in the combination [1]. Therefore, the equivalent resistance is 6 ̐.

Sources

1. [1] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > Activity 11.5 > p. 184