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Q24 (CDS-I/2025) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Basic mechanics concepts Answer Verified

The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is : (Take g = 10 m/s2)

Result
Your answer: —  Â·  Correct: A
Explanation

To find the minimum power required to lift the mass, we first calculate the work done against gravity. Work is defined as the product of force and distance. The force required to lift the mass at a constant speed is equal to its weight, calculated as F = m × g, where m is 50 kg and g is 10 m/s², resulting in 500 N. The work done (W) to lift this mass to a vertical distance (h) of 8 m is W = F × h = 500 N × 8 m = 4000 J. Power (P) is the rate of doing work, defined as P = W / t. Given the time (t) is 10 s, the power required is P = 4000 J / 10 s = 400 W. This represents the minimum power needed to overcome gravitational potential energy over the specified duration.

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