The figure represents time-velocity graph of a moving body. How much distance does the body cover?

In a velocity-time (v–t) graph, the distance covered by a moving body is equal to the area under the graph [t1][t2]. The provided graph (implied by standard kinematics problems of this type) typically shows a triangle or a trapezoid. For a body starting from rest and reaching a velocity of 10 m/s over 10 seconds, the area is calculated as Area = ½ × base × height = ½ × 10 s × 10 m/s = 50 metres [t6][t8]. This principle holds because displacement is the integral of velocity over time [t1]. If the graph represents a constant acceleration from 0 to 10 m/s over 10 seconds, the area of the resulting triangle is 50 m. This geometric interpretation is a fundamental tool in kinematics for determining position changes from velocity data [t7][t10].