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Q61 (NDA-I/2010) Science & Technology › Basic Science (Physics, Chemistry, Biology) › Geometrical optics Answer Verified

The ratio of the focal length of the objective to the focal length of the eyepiece is greater than one for

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Explanation

In optical instruments, the ratio of the focal length of the objective ($f_o$) to the focal length of the eyepiece ($f_e$) determines the angular magnification. For a telescope, the magnification is given by $M = f_o / f_e$. To achieve high magnification of distant objects, telescopes are designed with a long focal length objective and a short focal length eyepiece, making the ratio $f_o / f_e > 1$. For example, a telescope might have a 1500mm objective and a 25mm eyepiece. Conversely, in a compound microscope, the objective has a very short focal length to produce a high linear magnification of a nearby object, while the eyepiece has a relatively larger focal length to further magnify that image. Therefore, in a microscope, the ratio $f_o / f_e$ is typically less than one, whereas for a telescope, it is greater than one.

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