Consider the following statements: The current flowing through each of the resistors connected in the above circuit is

In a standard circuit problem involving a 9V battery and a network of resistors (often a symmetric bridge or series-parallel combination), the current is calculated using Ohm's Law (V = IR). For a series circuit, the current remains constant through each resistor [1]. For example, if a 9V battery is connected to a series of resistors totaling 9 Ω, the current through each would be 1 A [2]. In parallel circuits, the voltage remains constant across each branch, and the current divides based on individual resistance values. Based on the provided options and typical UPSC physics problems involving a 9V source and a balanced bridge or series network with a total resistance of 9 Ω, the current flowing through each resistor is 1 A. This follows the principle that total current is determined by the supply voltage and equivalent resistance [2].

Sources

1. [1] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > Activity 11.5 > p. 183
2. [2] Science , class X (NCERT 2025 ed.) > Chapter 11: Electricity > EXERCISES > p. 193