There is a ball of mass 320 g. It has 625 J potential energy when released freely from a height. The speed with which it will hit the ground is

According to the Law of Conservation of Energy, when an object is released from a height, its total potential energy (PE) is converted into kinetic energy (KE) just before it hits the ground (ignoring air resistance).

The formula for Kinetic Energy is: KE = ½ mv²

• Given: Potential Energy (PE) = 625 J
• Mass (m): 320 g = 0.32 kg (converted to SI units)

Setting PE equal to KE:

625 = ½ × 0.32 × v²
625 = 0.16 × v²
v² = 625 / 0.16
v² = 3906.25
v = √3906.25 = 62.5 m/s

Therefore, the speed with which the ball hits the ground is 62.5 m/s, making Option A the correct answer.