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Q63
(NDA-II/2024)
Science & Technology › Basic Science (Physics, Chemistry, Biology)
Official Key
Two resistances of 5.0 22 and 7.0 2 are connected in series and the combination is connected in parallel with a resistance of 36.0 2. The equivalent resistance of the combination of three resistors is
Result
Your answer:
—
·
Correct:
C
Explanation
The equivalent resistance of the circuit is calculated in two distinct steps based on the principles of series and parallel combinations:
- Step 1: Series Combination - When resistors are connected in series, their resistances are additive. The sum of the first two resistors is:
Rseries = 5.0 Ω + 7.0 Ω = 12.0 Ω. - Step 2: Parallel Combination - This 12.0 Ω combination is then connected in parallel with a 36.0 Ω resistor. The formula for equivalent resistance (Req) in parallel is:
1/Req = 1/R1 + 1/R2
1/Req = 1/12.0 + 1/36.0 - Final Calculation: Using a common denominator of 36.0:
1/Req = (3 + 1) / 36.0 = 4 / 36.0
Req = 36.0 / 4 = 9.0 Ω.
Thus, the equivalent resistance of the entire combination is 9.0 Ω, which aligns with Option C.
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