What is the number of atoms in 46 g of sodium-23 (iV=Avogadro constant)?

To determine the number of atoms in 46 g of sodium-23, one must first calculate the number of moles. The molar mass of sodium-23 is approximately 23 g/mol. Using the formula for moles (mass divided by molar mass), 46 g of sodium corresponds to 2 moles (46 g / 23 g/mol = 2 moles). According to the mole concept, one mole of any substance contains the Avogadro constant (N) number of particles. Therefore, the total number of atoms in 2 moles of sodium is calculated by multiplying the number of moles by the Avogadro constant (2 × N). This results in 2 N atoms, which is equivalent to approximately 1.2044 × 10^24 atoms.