A circuit has a fuse having a rating of 5 A. What is the maximum number of 100W-220V bulbs that can be safely connected in parallel in the circuit?

To determine the maximum number of bulbs, we first calculate the current drawn by a single 100W-220V bulb using the power formula P = VI, or I = P/V. For one bulb, the current is 100W / 220V, which is approximately 0.4545 A. In a parallel circuit, the total current is the sum of the currents flowing through each individual branch. The circuit is protected by a 5 A fuse, which represents the maximum allowable total current. To find the maximum number of bulbs (n), we use the inequality n × 0.4545 A ≤ 5 A. Solving for n gives n ≤ 5 / 0.4545, which equals approximately 11.001. Therefore, a maximum of 11 bulbs can be safely connected in parallel without exceeding the 5 A fuse rating.